Wednesday, 20 October 2010

Athlete's Problem

Question
An athlete covers 3 consecutive miles by walking the first mile, running the second and cycling the third. He runs twice as fas as he walk, and cycles one and a half times as fast as he runs. He takes 10 minutes longer than he would do if he cycled the three miles.
How long does he take by walking, cycling and running?


Answer




Distance
Time
Speed
Walk
1
1/X
X (Let ‘x’ be walking speed)
Run
1
1/2X
2X (He runs twice as fast as he runs)
Cycle
1
1/3X
3X ( He cycles one and a half times as fast as he runs)


T = D/S
T = 1+1+1/3X
T = 3/3X


10 minutes = 10/60 = 1/6


1/6 + 3/3X = 1/X + 1/2X + 1/3X (*6X)
X + 6 = 6 + 3 +2
X = 5


So:

  • walking = 1/5 
  • running = 1/10
  • cycling = 1/15
1/5 + 1/10 + 1/15 = 11/30 = 22/60


22 minutes

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